01
Formula
Force = pressure × area × efficiency.
Fpush = P × πB² ÷ 4 × η. Fpull = P × π(B² − R²) ÷ 4 × η. Bore for pull = √(4F ÷ (πPη) + R²). Maximum rod for pull = √(B² − 4F ÷ (πPη)). Use PSI, inches, and efficiency as a decimal to obtain pounds-force.
02
Example
A 4-inch bore with a 2-inch rod at 2,000 PSI.
At 90% force efficiency, the full piston area is 12.566 square inches and rod-side area is 9.425 square inches. Estimated extension force is 22,619.47 lbf; retraction is 16,964.60 lbf. In Bore mode, 20,000 lbf at the same PSI and efficiency needs 3.761 inches for push, or 4.260 inches for pull with a 2-inch rod. Select an adequately rated standard bore above the calculated minimum.
03
Tips
Check the whole load path, not just the bore.
Use pressure available at the cylinder, not the pump's maximum rating. Return-side backpressure subtracts a separate pressure-times-area force and is not modeled here. A long exposed rod, side load, mounting geometry, and acceleration can govern selection even when this force estimate looks sufficient. Have the equipment manufacturer verify rod buckling, seals, mounts, and pressure ratings.
04
Equipment
Finance hydraulic equipment, not pounds of force.
A press, hydraulic power unit, or other eligible hydraulic equipment purchase is the financing context. No force or diameter result is passed as a loan amount. Dengaro is a financing broker and a brand of Funding Routes LLC, not the lender. Approval, rates, and terms are not promised.